Episode 3072 2019 WPA World Ten-ball Championship Thu, 2025-Oct-02 00:42 UTC Length - 2:28
Direct Link Welcome to featured Wiki of the Day, your daily dose of knowledge from Wikipedia's finest articles.
The featured article for Thursday, 2 October 2025, is 2019 WPA World Ten-ball Championship.
The 2019 WPA World Ten-ball Championship was a professional pool tournament for the discipline of ten-ball organised by the World Pool-Billiard Association (WPA) and CueSports International. It was the fifth WPA World Ten-ball Championship; the previous championship was held in 2015. After plans for an event in both 2016 and 2018 to be held in Manila fell through, a 2019 event at the Rio All-Suite Hotel & Casino in Las Vegas as part of a three-year deal for the event to be played in the United States was agreed. The event was held concurrently with the Billiard Congress of America's National Ten-ball event from July 22 to 26. The event was sponsored by cue manufacturer Predator Group.
The competition featured 64 participants, selected according to world and continental pool rankings as well as qualifying events. The tournament was played as a double-elimination bracket until 16 players remained, at which point it changed to a single-elimination format. Ko Ping-chung, representing Chinese Taipei, won the event, defeating German player Joshua Filler 10–7 in the final. Ko's brother Ko Pin-yi, who was the defending champion, lost to Filler 10–8 in the semi-final. The event featured a prize fund of $132,000, the winner receiving $30,000.
This recording reflects the Wikipedia text as of 00:42 UTC on Thursday, 2 October 2025.
For the full current version of the article, see 2019 WPA World Ten-ball Championship on Wikipedia.
This podcast uses content from Wikipedia under the Creative Commons Attribution-ShareAlike License.
Visit our archives at wikioftheday.com and subscribe to stay updated on new episodes.
Follow us on Bluesky at @wikioftheday.com.
Also check out Curmudgeon's Corner, a current events podcast.
Until next time, I'm standard Aditi.
|
|